hughmcguire
//page097_example2.44_2 ¬[∃x(r(x) ∧ s(x))]
| (#) | Comments | Theorem and subgoals | |
|---|---|---|---|
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We start working with the formula being proved as follows: |
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| (1) | page097_example2.44_2 |
¬[∃x(r(x) ∧ s(x))] |
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≡ by rewriting the form "¬∃ν[φ]"to " ∀ν[¬φ]" |
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| (2) |
∀x¬(r(x) ∧ s(x)) |
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≡ by rewriting the form "¬(φ1 ∧ φ2)"to " (¬φ1 ∨ ¬φ2)" |
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| (3) | [unused] |
∀x(¬[r(x)] ∨ ¬[s(x)]) |
identification:
1234112711454
1234112693034
18420